I've followed the instructions from the official react-native-firebase documentation and everything, as per the instructions, works fine.
It is my understanding that I should be able to create a link like the following in the Firebase Dynamic Links console: https://myapp.page.link/offer?offerid=123456 and be able to receive the offerid parameter in my app. However, when I click that link (in the iOS simulator, Android emulator, and on a real device) the app opens, but I just get a link with the following data:
Received initial link {"minimumAppVersion": null, "url": "https://mysite.co/offers"}There are no query string parameters attached. Am I missing something in the Firebase Dynamic Link configuration? Or in my implementation of react-native-firebase that was not covered in the documentation linked above? Or is this actually just not possible?
